minimum refractive index of prism

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minimum refractive index of prism

written 8.3 years ago by

teamques10 ★ 66k

• modified 8.3 years ago

A 45° - 45° - 90° prism is immersed in alcohol (n = 1.45). What is the minimum refractive index the prism must have if a ray incident normally on one of the short faces is to be totally reflected at the long face of a prism?

Mumbai University > Electronics and Telecommunication > Sem7 > Optical Communication and Networks

Marks: 5M

Year: May 2012

optical networks

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written 8.3 years ago by

teamques10 ★ 66k

• modified 8.3 years ago

Given: $θ_c$= 45°

$n_1$ = 1.45

To find: refractive index $n_2$

Solution:

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$θ_c= sin^{-1} \frac{ n_2}{n_1} $

$sin^{-1} \frac{n_2}{n_1}$ = 45°

$\frac{n_2}{n_1}$ = sin 45 = 0.707

$n_{2}$ = 1.45 * 0.707

= 1.025

$n_2$= Minimum refractive index= 1.025

$$\boxed{Minimum \ \ \ refractive \ \ \ index(n_2)= 1.025}$$

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