A simple supported beam of 6m carries idl of 10kN/m upto 2m and couple of 5kNm (clockwise) at 3m respectively from left side support.Draw SFD and BMD with appropriate calculation.

3views

written 5.5 years ago by

teamques10 ★ 69k

$\begin{array}{l}{\text { Data: } \mathrm{L}=6 \mathrm{m}, \mathrm{W}_{1}=18 \mathrm{kN}, \mathrm{W}_{2}=18 \mathrm{kN}, \sigma_{\mathrm{b}}=10 \mathrm{N} / \mathrm{mm}^{2}, \mathrm{b}=\mathrm{d}} \ {\text { Find: } \mathrm{b}, \mathrm{d}}\end{array}$

$\begin{array}{l}{\mathrm{RA}=\mathrm{RB}=18 \mathrm{kN} \text { (Due to symmetry) }} \ {\mathrm{M}_{\max }=\mathrm{M}_{\mathrm{C}}=\mathrm{M}_{\mathrm{D}}=18 \times 2=36 \mathrm{kN}-\mathrm{m}=36 \times 10^{6} \mathrm{N}-\mathrm{mm}} \ {\mathrm{I}=\frac{\mathrm{bd}^{3}}{12}=\frac{\mathrm{b}^{4}}{12}} \ {\mathrm{Y}=\frac{\mathrm{d}}{2}=\frac{\mathrm{b}}{2}}\end{array}$ $$ \begin{array}{l}{\frac{\mathrm{M}}{\mathrm{I}}=\frac{\sigma}{\mathrm{Y}}} \ …

Create a free account to keep reading this post.

and 5 others joined a min ago.

ADD COMMENT EDIT