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Find centroidal moment of inertia about X-X axis of 'symmetrical I' section with flanges 200mm x 12 mm. and web 10 mm. x 300 mm.
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$$ \begin{array}{l}{\mathrm{I}_{\mathrm{xx}}=\frac{\mathrm{BD}^{3}-\mathrm{bd}^{3}}{12}} \\ {\mathrm{I}_{\mathrm{xx}}=\frac{200 \times 324^{3}-190 \times 300^{3}}{12}} \\ {\mathrm{I}_{\mathrm{xx}}=139.37 \times 10^{6} \mathrm{mm}^{4}}\end{array} $$

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