$C_aH_bO_cN_d + (4a+b-2c-3d/4) O_2 ⇒ aCO_2 + (b-3d/2) H_2O +dNH_3$

Step 1: Determine the oxygen requirements:

Given equation is:

$C_aH_bO_cN_d + (4a+b-2c-3d/4) O_2 ⇒ aCO_2 + (b-3d/2) H_2O +dNH_3$

Given composition: $C_{55}H_{110}O_{35}N_1$

The required coefficients are: a=55, b=110, c=35, d=1

Using the coefficient we get the equation:

$C_{55}H_{110}O_{35}N_1 + 64.25 O_2 ⇒ 55CO_2 + 53.5H_2O +NH_3 \\ (1344)\hspace{1.5cm}(2056)\hspace{1cm}(2420)\hspace{0.6cm}(963)\hspace{0.7cm}(17)$

Oxygen required /tonne$= 2056*1000/1344 \\ = 1530 kg/tonne…………………..1$

Step 2: Determine the oxygen required to stabilize ammonia:

$NH3 + 2O2 ⇒ H2O +HNO3 \\ (17)\hspace{0.7cm}(64)\hspace{0.6cm}(18)\hspace{0.5cm}(63)$

Amount of oxygen required$= 64*1000/1344 \\ = 47.61 kg/tonne…………………….2$

Step 3:

Total amount of oxygen$=1530 + 47.61 \\ = 1578 kg/tonne.$