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A simply supported beam of 4 m length carries two point loads of 5 kN and 7 kN at 1.5 m and 3.5 m from the left hand support respectively. Draw SFD and BMD.
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ΣMA=0+ve

5 x 1.5 + 7 x 3.5 - RB×4=0

RB=8kN

ΣFy+ve,

RA+RB57=0

RA=128=4kN

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S.F. Calculations +ve

S.FA=4kN

S.FC(left)=4kN

S.FC(right)45=1kN

S.FD(left)=1kN

S.FD(right)=17=8kN

S.FB=8kN

B.M. Calculations +ve

B.MA=B.MB=0

B.Mc=4×1.5=6KN

B.MD=4×3.55×2

=4kNm

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