A solid shaft of diameter 110 mm transmits a torque of 12.5 kN.m. Calculate maximum shear stress in material of shaft and angle of twist in radians for a length of 2.5 m. Take G = 80 GPa.

3.0kviews

written 5.6 years ago by

teamques10 ★ 69k

• modified 5.6 years ago

need-tagging

ADD COMMENT EDIT

1 Answer

562views

written 5.6 years ago by

teamques10 ★ 69k

Given: For solid shaft, d = 110 mm , R = 55 mm, T = 12.5 kN-m = $12.5 \times 10^{6} N-mm$ , L = 2.5m = 2500 mm, G = 80 GPa = $80 \times 10^{3} N/mm^{2}$

Solution:

$Polar M.I = I_{p} = \frac{\pi}{32} d^{4} = \frac{\pi}{32} \times 110^{4} …

Create a free account to keep reading this post.

and 2 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.