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Two steel rods and one copper rod each 20 mm in diameter together support a load of 20kN as shown in fig. Find the stresses in rod, Es = 210 GPa and Ec = 110 GPa.

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Data: ds = 20mmΦ, dc = 20mmΦ, Ls = 2m, Lc = 1.5m, P = 20kN, Es = 210 GPa and Ec = 110 GPa.

As=2×(πd2s4)=2×(π×2024)=628.32mm2

Ac=(πd2c4)=(π×2024)=314.16mm2

P=Ps+Pc

p=σsAs+σcAc

20×103=σs628.32+σc314.16

σsLsEs=σcLcEc

σs×2000210×103=σc×1500110×103

σs=1.43σc

20×103=(1.43σc)628.32+σc314.16

σc=16.49N/mm2

σs=1.43σc

σs=1.43×16.49=23.58N/mm2

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