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Calculate the safe stopping sight distance for a design speed of 50 Kmph for a two way traffic in a single lane road. Assume f = 0.37 and reaction time = 2.5 seconds.

written 5.3 years ago by teamques10 ★ 68k

modified 2.6 years ago by pedsangini276 • 4.8k

transportation engineering

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written 5.3 years ago by teamques10 ★ 68k

Given data:

V = 50 Kmph

t = 2.5 seconds

f = 0.37

SSD = 0.278 V t + ( V²/ 254 f)

= (0.278 x 50 x 2.5 ) + ( 50²/ ( 254 x 0.37))

= 34.75 + 26.60

SSD = 61.35 m. for one way traffic.

SSD for Two Way traffic on single lane road = 2 x SSD for one way traffic

= 2 x 61.35 m

= 122.70 m say 123 m

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