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(1) overlap-add method: x(n)=2,2,1,1,2h(n)=1,3
x1(n)=2,2,1,0x2(n)=1,1,2,0,}2 sequence
h(n)=1,3,0,0
No . of overlap =No. of samples in h(n) ----1
y1(n)=x1(n)(N)h(n)
$\left[\begin{array}{llll}{1} & {0} & {0} & {3} \\ {3} & {1} & {0} & {0} \\ {0} …