$$C_aH_bO_cN_d + (4a+b-2c-3d/4) O_2 ⇒ aCO_2 + (b-3d/2) H_2O +dNH_3$$

$Solution: \\ Step \ \ 1: Determine \ \ the \ \ oxygen \ \ requirements: \\ Given \ \ equation \ \ is:$

$$C_aH_bO_cN_d + (4a+b-2c-3d/4) O_2 ⇒ aCO_2 + (b-3d/2) H_2O +dNH_3$$

Given composition: $C_{45}H_{80}O_{40}N$

The required coefficients are: a=45, b=80, c=40, d=1

Using the coefficient we get the equation:

$C_{45}H_{80}O_{40}N + 44.25 O_2 ⇒ 45CO_2 + 38.5H_2O +NH_3 \\ (1274) \ \ \ \ \ \ \ \ \ \ \ \ \ \ (1416) \ \ \ \ \ \ \ \ \ \ (1980) \ \ \ \ \ \ (693) \ \ \ \ \ \ \ \ \ \ \ (17)$

Oxygen required /tonne$= 1416*1000/1274 \\ = 1111.46 kg/tonne…………………..1$

Step 2: Determine the oxygen required to stabilize ammonia:

$NH_3 + 2O_2 ⇒ H_2O +HNO_3 \\ (17) \ \ \ \ \ (64) \ \ \ \ \ \ \ \ (18) \ \ \ \ (63)$

Amount of oxygen required$= 64*1000/1274 \\ = 50.23 kg/tonne…………………….2$

Step 3: Determination of amount of air requirement:

Assume 23.15% oxygen by weight

Density of air= 1.2928 kg/m3

Total amount of oxygen$= 1111.46 +50.23 \\ =1162 kg/tonne$

Mass of air required$= 1162/0.2315 \\ = 5020 kg/tonne$

Volume of air required$= 5020/1.2928 \\ = 3883 m3/tonne$