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Find the circular convolution of the sequences x(n)={1,2,1,2} and h(n)={4,0,4,0}
1 Answer
written 5.6 years ago by |
In matrix form,
[yp(n)]4×1=[xp(n)]4×4[hp(n)]4×1
$\left[\begin{array}{c}{y_{p}(0)} \\ {y_{p}(1)} \\ {y_{p}(2)} \\ {y_{p}(3)}\end{array}\right]=\left[\begin{array}{cccc}{x_{p}(0)} & {x_{p}(3)} & {x_{p}(2)} & {x_{p}(1)} \\ {x_{p}(1)} & {x_{p}(0)} & {x_{p}(3)} & {x_{p}(2)} \\ {x_{p}(2)} & {x_{p}(1)} & {x_{p}(0)} & {x_{p}(3)} \\ {x_{p}(3)} & {x_{p}(2)} & {x_{p}(1)} & {x_{p}(0)}\end{array}\right] \times\left[\begin{array}{c}{h_{p}(0)} \\ {h_{p}(1)} …