set-1	set-2
$\bar{x}=82.5$	$\bar{x}=48.75$
$\sigma=7.3$	$\sigma=8.35$

Which of the two sets is more consistent?

Solution:

$Coefficient of variance V=\frac{\sigma}{\overline{x}} \times 100$

For set-I

$V_{1}=\frac{7.3}{82.5} \times 100$

$\therefore V_{1}=8.848$

For set-II

$V_{2}=\frac{8.35}{48.75} \times 100$

$\therefore V_{2}=17.128$

$\therefore V_{1} \lt V_{2}$

$\therefore Set-I is more consistent$