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prove that sin−1(35)−sin−1(817)=cos−1(8485)
1 Answer
written 5.6 years ago by |
Solution:
Letsin−1(35)=A
∴sinA=35
∴cos2A=1−sin2A
=1−925
=1625
∴cosA=45
$\begin{aligned} \sin ^{-1}\left(\frac{8}{17}\right)=B \\ & \therefore \sin B=\frac{8}{17} \\ & \therefore \cos ^{2} B \\ &=1-\sin ^{2} B \\ & = 1-\frac{64}{289} \\ & = \frac{225}{289} \\ \therefore \cos B=& \frac{15}{17} \therefore …