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Find the value of $sin(15^{o})$ using compound angles

written 5.2 years ago by teamques10 ★ 68k

modified 2.6 years ago by pedsangini276 • 4.8k

engineering mathematics

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written 5.2 years ago by teamques10 ★ 68k

Solutioin:

$\sin \left(15^{\circ}\right)$

$=\sin \left(45^{\circ}-30^{\circ}\right)$

$=\sin 45^{\circ} \cos 30^{\circ}-\cos 45^{\circ} \sin 30^{\circ}$

$=\left(\frac{1}{\sqrt{2}}\right)\left(\frac{\sqrt{3}}{2}\right)-\left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right)$

$=\frac{\sqrt{3}-1}{2 \sqrt{2}} \quad or 0.2588$

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