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Find the equation of line passing through (3,4) and perpendicular to the line 2x-3y+5=0

written 5.2 years ago by teamques10 ★ 68k

modified 2.6 years ago by pedsangini276 • 4.8k

engineering mathematics

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written 5.2 years ago by teamques10 ★ 68k

Solution:

$Point =\left(x_{1}, y_{1}\right)=(3,4)$

$Slope of the line 2 x-4 y+5=0 is,$

$$ m=-\frac{a}{b}=-\frac{2}{-4}=\frac{1}{2} $$

$Slope of the required line is,$

$m = -\frac{1}{m} = -2$

$\therefore equation is ,$

$y - y_{1} = m(x - x_{1})$

$\therefore y - 4 = -2(x - 3)$

$\therefore 2x + y - 10 = 0$

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