Find the length of the perpendicular from the point (5,4) on the straight line 2x+y=34.

5.9kviews

written 5.2 years ago by

teamques10 ★ 68k

modified 2.6 years ago by

pedsangini276 • 4.8k

engineering mathematics

ADD COMMENT EDIT

3 Answers

808views

written 5.2 years ago by

teamques10 ★ 68k

Solution:

$p=\left|\frac{a x_{1}+b y_{1}+c}{\sqrt{a^{2}+b^{2}}}\right|$

$=\left|\frac{2(5)+1(4)-34}{\sqrt{(2)^{2}+(1)^{2}}}\right|$

$=\left|\frac{10+4-34}{\sqrt{5}}\right|$

$=\frac{20}{\sqrt{5}} OR 8.94$

ADD COMMENT EDIT

323views

written 5.2 years ago by

teamques10 ★ 68k

Solution:

$p=\left|\frac{a x_{1}+b y_{1}+c}{\sqrt{a^{2}+b^{2}}}\right|$

$=\left|\frac{2(5)+1(4)-34}{\sqrt{(2)^{2}+(1)^{2}}}\right|$

$=\left|\frac{10+4-34}{\sqrt{5}}\right|$

$=\frac{20}{\sqrt{5}} OR 8.94$

ADD COMMENT EDIT

165views

written 5.2 years ago by

teamques10 ★ 68k

Solution:

$p=\left|\frac{a x_{1}+b y_{1}+c}{\sqrt{a^{2}+b^{2}}}\right|$

$=\left|\frac{2(5)+1(4)-34}{\sqrt{(2)^{2}+(1)^{2}}}\right|$

$=\left|\frac{10+4-34}{\sqrt{5}}\right|$

$=\frac{20}{\sqrt{5}} OR 8.94$

ADD COMMENT EDIT

Please log in to add an answer.