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Without using calculator find the value of cos570sin510+sin(330)cos(390)
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Solution:

cos570=cos(6×90+30)

cos570=cos30=32

sin510=sin(6×9030) =sin30=12

sin(330)=sin(330) =sin(4×9030)=(sin30)=12 cos(390)=cos390 =cos(4×90+30)=cos30=32

$\therefore \cos 570^{\circ} \sin 510^{\circ}+\sin \left(-330^{\circ}\right) \cos …

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