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Find the value of $log\big(\frac{2}{3}\big) + log\big(\frac{4}{5}\big) - log\big(\frac{8}{15}\big)$
1 Answer
written 5.2 years ago by |
Solution:
$log\big(\frac{2}{3}\big) + log\big(\frac{4}{5}\big) - log\big(\frac{8}{15}\big) = log\big(\frac{2}{5} x \frac{4}{5}\big) - log\big(\frac{8}{15}\big)$
$= log\big(\frac{8}{15}\big)- log\big(\frac{8}{15}\big)$
$= 0 OR log\Bigg(\frac{\frac{8}{15}}{\frac{8}{15}}\Bigg)$
$= log(1) = 0$