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Find the distance between the parallel lines 3x-y+7=0 and 3x-y+16=0
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Solution:

For 3x-y+7=0

a=3,b=1,c1=7

For 3x-y+16=0

a=3,b=1,c2=16

Distance between two parallel lines is

=|c2c1a2+b2|=|16732+(1)2|

=|910|

=910.OR2.846

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