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Resolve into partial fraction x3−x+3(x−2)(x2+1)
1 Answer
written 5.6 years ago by |
Solution:
x2−x+3(x−2)(x2+1)=Ax−2+Bx+Cx2+1
x2−x+3=(x2+1)A+(x−2)(Bx+C)
Put x=2
5 = 5A
A = 1
put x = 0
3 = A - 2C
C = 1
put x = 1
3 = 2A + (-1)(B+C)
3 = 2 - …