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Resolve into partial fraction x3x+3(x2)(x2+1)
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Solution:

x2x+3(x2)(x2+1)=Ax2+Bx+Cx2+1

x2x+3=(x2+1)A+(x2)(Bx+C)

Put x=2

5 = 5A

A = 1

put x = 0

3 = A - 2C

C = 1

put x = 1

3 = 2A + (-1)(B+C)

3 = 2 - …

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