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prove that cos20cos40cos60cos80 = 116
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Solution:

L.H.S = cos20cos40cos60cos80

= cos20cos4012cos80

= 14(2cos20cos40)cos80

= 14(cos60 + cos20)cos80

= 14(12+Cos20)Cos80

= 14(12Cos80+Cos20Cos80)

= 18(Cos80+2Cos20Cos80)

= 18(Cos80 + Cos100 + Cos60)

= 18(Cos80+Cos100+12)

= 14(Cos80+Cos(π80)+12)

= $\frac{1}{8}\big(Cos80 - Cos80 + \frac{1}{2} …

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