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If A=30o, verify that i) sin2A = 2sinAcosA ii) cos2A = 1tan2A1+tan2A
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Solution:

I) L.H.S = sin2A

= sin2(30o)

= 2sin60o

= 32

R.H.S = 2Sin2CosA

=2Sin300Cos30o

=2(12)(32)

=32

hence, SIn2A = 2SinACosA

ii) L.H.S = cos2A=cos2(30o)

=cos60o

=12

R.H.S = 1tan2A1+tan2A

=1tan230o1+tan230o

=1(13)21+(13)2

=12

hence, Cos2A=1tan2A1+tan2A

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