0

26kviews

Compute the standard deviation for 15 , 22 , 27 , 11 , 9 , 21 , 14 , 9.

written 5.6 years ago by teamques10 ★ 69k

modified 3.0 years ago by pedsangini276 • 4.8k

engineering mathematics

ADD COMMENT FOLLOW SHARE EDIT

1 Answer

0

7.7kviews

written 5.6 years ago by teamques10 ★ 69k

Solution:

$x_{i}$	$d_{i}=x_{i}-\bar{x}$	$d_{I}^{2}$
15	-1	1
22	6	36
27	11	121
11	-5	25
9	-7	49
21	5	25
14	-2	4
9	-7	49
$\sum_{128} x_{i}=$		$\sum_{310} d_{i}^{2}$

$\operatorname{Mean} \overline{x}=\frac{\sum x_{i}}{n}$

Mean $\overline{x}=\frac{128}{8}=16$

$Standard deviation \sigma=\sqrt{\frac{\sum d_{i}^{2}}{n}}$

$\begin{aligned} &=\sqrt{\frac{310}{8}} \\ &=6.22 \end{aligned}$

ADD COMMENT SHARE EDIT