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Compute the standard deviation for 15 , 22 , 27 , 11 , 9 , 21 , 14 , 9.

written 5.2 years ago by teamques10 ★ 68k

modified 2.6 years ago by pedsangini276 • 4.8k

engineering mathematics

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1 Answer

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written 5.2 years ago by teamques10 ★ 68k

Solution:

$x_{i}$	$d_{i}=x_{i}-\bar{x}$	$d_{I}^{2}$
15	-1	1
22	6	36
27	11	121
11	-5	25
9	-7	49
21	5	25
14	-2	4
9	-7	49
$ \sum_{128} x_{i}= $		$\sum_{310} d_{i}^{2}$

$\operatorname{Mean} \overline{x}=\frac{\sum x_{i}}{n}$

Mean $\overline{x}=\frac{128}{8}=16$

$Standard deviation \sigma=\sqrt{\frac{\sum d_{i}^{2}}{n}}$

$ \begin{aligned} &=\sqrt{\frac{310}{8}} \\ &=6.22 \end{aligned} $

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