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Using Cramers rule, solve x-y-2z=1; 2x+3y+4z=4; 3x-2y-6z=5
written 5.6 years ago by | modified 3.0 years ago by |
solution:
D = [1−1−2 234 3−2−6]
= 1(-18+8)+1(-12-12)-2(-4-9)
=-8
Dx = [1−1−2 434 5−2−6]
= 1(-18+8) +1(-24-20) -2(-8-15)
= -8
therefore, X=DxD=−8−8=1
Dy = [11−2 244 35−6]
=1(-24-20) -1(-12-12)-2(10-12)
=-16
therefore, y = DyD=−16−8=2
Dz = [1−11 234 3−25]
=1(15+8) +1(10-12)+1(-4-9)
= 8
therefore, y = DzD=8−8=−1
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