0
4.0kviews
Resolve into partial fractions : x+3(x1)(x+1)(x+5)
1 Answer
0
974views

Solution:

x+3(x1)()x+1)(x+5) = Ax1 + Bx+1 + Cx+5

therefore, x+3 = A(x+1)(x+5) +B (x-1)(x+5) +C(x-1)(x+1)

put x = 1

4=A(2)(6)

4=12A

hence, A = 13

put x = -1

-1 + 3 = B(-2)(4)

2 = -8B

hence, B = 14

put x = -5

-5 + 3 = C(-6)(-4) …

Create a free account to keep reading this post.

and 4 others joined a min ago.

Please log in to add an answer.