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Resolve into partial fractions : x+3(x−1)(x+1)(x+5)
1 Answer
written 5.6 years ago by |
Solution:
x+3(x−1)()x+1)(x+5) = Ax−1 + Bx+1 + Cx+5
therefore, x+3 = A(x+1)(x+5) +B (x-1)(x+5) +C(x-1)(x+1)
put x = 1
4=A(2)(6)
4=12A
hence, A = 13
put x = -1
-1 + 3 = B(-2)(4)
2 = -8B
hence, B = −14
put x = -5
-5 + 3 = C(-6)(-4) …