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If the volume of the sphere is $\frac{4 \small \pi}{3} cm^{3}$. Find its surface area
written 5.3 years ago by gravatar for teamques10 teamques10 ★ 68k modified 2.7 years ago by gravatar for pedsangini276 pedsangini276 • 4.8k
jee mathematics
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written 5.3 years ago by gravatar for teamques10 teamques10 ★ 68k

Solution:

Volume of sphere $=\frac{4}{3} \pi r^{3}$ \begin{aligned} \therefore \frac{4 \pi}{3} &=\frac{4}{3} \pi r^{3} \ 1=& r^{3} \ \therefore r=1 \ \text { Surface area of sphere } &=4 \pi r^{2} \ &=4 \pi(1)^{2} \ &=4 \pi \text { OR } 12.56 \mathrm{cm}^{2} \end{aligned}
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written 5.3 years ago by gravatar for teamques10 teamques10 ★ 68k

Solution:

Volume of sphere $=\frac{4}{3} \pi r^{3}$ \begin{aligned} \therefore \frac{4 \pi}{3} &=\frac{4}{3} \pi r^{3} \ 1=& r^{3} \ \therefore r=1 \ \text { Surface area of sphere } &=4 \pi r^{2} \ &=4 \pi(1)^{2} \ &=4 \pi \text { OR } 12.56 \mathrm{cm}^{2} \end{aligned}
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