written 8.4 years ago by | modified 2.8 years ago by |
Mumbai University > Electronics and Telecommunication > Sem 5 > RF Modeling and Antennas
Marks: 5M
Year: Dec 2014
written 8.4 years ago by | modified 2.8 years ago by |
Mumbai University > Electronics and Telecommunication > Sem 5 > RF Modeling and Antennas
Marks: 5M
Year: Dec 2014
written 8.4 years ago by | • modified 8.4 years ago |
The basic methodology for analyzing an array of identical elements is established.
As shown in Fig.5 (a), let us consider an array of N identical elements. The position vector of the ith element is given by $r_i$. The excitation of $i^{th}$ element is given $C_ie^{js_i}$; where $C_i$ and $a_i$ are respectively the relative amplitudes and phases.
Let the electric field radiated by an element, when placed at the origin and with an unity excitation is given by
$$E(r) = f(θ, ϕ)\frac{e^{-jk_0r}}{4πr}................... (1)$$
The distance from the $i^{th}$ element to the far field point of interest is $R_i = r - \hat{a}_rr_i$for phase variation and $R_i = r$ for amplitude variation.
The total electric field at the point P is given by
$E(r)$ $= \sum_{i = 1}^N C_ie^{ja_i}f(θ, ϕ)\frac{e^{jk_0\left(r - \hat{a}_r.r_i\right)}}{r} \\ = f(θ, ϕ)\frac{e^{jk_0r}}{r}\sum_{i = 1}^N C_ie^{j\left(a_i+k_0\hat{a}_r . r_i\right)}...............(2)$
As can be seen from (2), the total radiation field is given by the product of the radiation field of the reference element and the term $$\sum_{i=1}^N C_ie^e \left(a_i + k_0 \hat{a}_r.r\right)$$
The term $F(θ, ϕ) = \sum_{i=1}^NC_ie^{j\left(a_i + k_0 \hat{a}_r.r_i\right)}............... (3)$
The directivity of the array $D(θ, ϕ) \infty |f(θ, ϕ)|^2|F(θ, ϕ)|^2$. Thus we find that the radiation pattern of an array is the product of the function of the individual element with the array pattern function. This termed as principle of pattern multiplication.