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P0=(x,y)=(3,4),P1=(x,y)=(10,7)
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Solution:

Px=[310][1110]{t1}=[310][t1t0]Px=3(t+1)+10Px=7t+3

Py=[47][1110]{t1}

Py=4(t+1)+7t

Py=3t+4

$\begin{array}{|c|c|c|c|c|c|c|}\hline t \rightarrow & {0} & {0.2} …

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