0
8.8kviews
Design 2 - Hydrodynamic lubricated journal bearing
1 Answer
written 5.4 years ago by |
The following data is given for 360° Hydrodynamic bearing.
Radial Load - 10KN
Journal Speed - 1450rpm
L/D Ratio - 1
Bearing Length - 50mm
Radial Clearance - 20 Microns
Eccentricity - 15 Microns
Sp. Gr. Of Lubricant - 0.86
Sp. Heat of Lubricant – 2.09 kJ kg°C
Calculate
Given Data
Type of Bearing = 360° Full Journal Hydro-dynamically Lubricated Bearing.
Journal Speed = 1450 rpm
n' = 24.16 rps
Load $W = 10 \times 10^3 N$
L/D=1
L = 50mm
Radial Clearance (Cr) - 20 Microns = $C= 2Cr = 40 \times 10^{-3} mm$
Eccentricity $(e) = 15 \times 10^3 mm$
Spa. Gravity = $ \rho = 0.86 $
Sp. Heat of Lubricant $(C)= 2.09 KJ/kg°C$
Solution