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Derive the equation for the correction couple to be applied to make two mass systems dynamically equivalent.
1 Answer
written 5.8 years ago by |
Solution:
Let,
L3 = Distance of ass placed at D from G,
I1 = New mass moment of inertia of 2 masses.
k1 = New radius of duration.
α = Angular acceleration of the body.
I= Mass moment of inertia of dynamically equivalent system.
KG = Radius of gyration of a dynamically equivalent system.
→ Torque required to accelerate body,
T=I.α
=m.(KG)2.α
→ Torque required to accelerate two mass system placed arbitariy.
T1=I1 α
=m.(k1)2.α
∴T= Correction couple = T1−T
T=mk21 α–mK2G α
=m α[k21–K2G]