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Derive the equation for the correction couple to be applied to make two mass systems dynamically equivalent.
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Solution:

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Let,

L3 = Distance of ass placed at D from G,

I1 = New mass moment of inertia of 2 masses.

k1 = New radius of duration.

α = Angular acceleration of the body.

I= Mass moment of inertia of dynamically equivalent system.

KG = Radius of gyration of a dynamically equivalent system.

Torque required to accelerate body,

T=I.α

=m.(KG)2.α

Torque required to accelerate two mass system placed arbitariy.

T1=I1 α

=m.(k1)2.α

T= Correction couple = T1T

T=mk21 αmK2G α

=m α[k21K2G]

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