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Gyroscopic Effect on Shaft Rotating Inside Bearing:
1 Answer
written 5.8 years ago by |
C=Iw.Wp
I=mk2
I=mr22=4×0.07522=0.011 kgm2
w=2π×80060=83.7755 rad/sec
wp=2πNp60=2π×5060=5.23 rad/sec
C=0.011×83.7755×5.23
C=4.81 Nm
∑MA=0↷+
- R_B \times 0.080 + 39.24 \times 0.040 \ – \ 4.81 = 0
R_B = -40.50N = 40.50N \ (\downarrow)
EM_B = 0 \curvearrowright +
R_A \ (0.080) – 39.24 \ (0.040) \ – \ 4.81 \ = \ 0
R_A \ = \ 79.74 \ N (\uparrow)