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Bow turns portside.
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$m = 900 \ kg$ $k = 0.6 \ m$ $N = 1800 \ rpm$ $\therefore$ $w = \frac{2 \pi \times 1800}{60}$

$\therefore w = 188.496 \ rad/sec$

Case 1:

$v = 40 \ km/hr$

$v = \frac{40 \times 10^3}{3600}$

$I = mk^2 = 324 \ kg m^2$

$w_p = …

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