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Compare Full converter and Semi converter

written 5.4 years ago by teamques10 ★ 68k

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written 5.4 years ago by teamques10 ★ 68k

Sr. No.	Parameter	Full Converter	Semi Converter
1	Average load voltage	$E_{\mathrm{dc}}=\frac{2 E_{m}}{\pi} \cos \alpha$	$E_{\mathrm{dc}}=\frac{E_{m}}{\pi}(1+\cos \alpha)$
2	RMS Load Voltage	$E_{\mathrm{rms}}=\frac{E_{m}}{\sqrt{2}}$	$E_{\operatorname{rms}}=\frac{E_{m}}{\sqrt{2}}\left[\frac{1}{\pi}\left(\pi-\alpha+\frac{\sin 2 \alpha}{2}\right)\right]^{1 / 2}$
3	Form factor (FF)	$\mathrm{F.F.}=\frac{\pi}{2 \sqrt{2} \cos \alpha}$	$\mathrm{F.F.}=E_{\mathrm{rms}} / E_{\mathrm{dc}}$
4	Ripple Factor (RF)	$\mathrm{RF}=\left[\frac{\pi^{2}}{8 \cos ^{2} \alpha}-1\right]^{1 / 2}$	$\mathrm{RF}=\left[\mathrm{FF}^{2}-1\right]^{1 / 2}$
5	Rectification Efficiency $(\eta)$	$\eta=\frac{8 \cos ^{2} \alpha}{\pi^{2}}$	$\eta=1 / \mathrm{FF}^{2}$
6	Operation	Two quadrant converter (Rectification and inversion)	Single quadrant converter (Rectification only)
7	Fundamental Power Factor $(\text { FPF })$	$\mathrm{FPF}=\cos \alpha$	$\mathrm{FPF}=\cos (\alpha / 2)$
8	Free wheeling Mode	Absent	Present
9	Input Power Factor (PF)	$\mathrm{PF}=\frac{2 \sqrt{2}}{\pi} \cos \alpha$	$\mathrm{PF}=\frac{\sqrt{2}(1+\cos \alpha)}{[\pi(\pi \alpha)]^{1 / 2}}$
10	Supply current	Square-wave	Quasi-square wave
11	Harmonic present in supply current	Only odd harmonics	Only odd harmonics
12	Power Flow	Bidirectional	Unidirectional

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