The single phase half-wave controlled rectifier with inductive-load is shown in Fig.1.a The waveshapes for voltage and current in case of an inductive load are given in Fig.1.b. The load is assumed to be highly inductive.

The operation of the circuit on inductive loads changes slightly. Now at instant $t_{01}$ , when the thyristor is triggered, the load-current will increase in a finite-time through the inductive load. The supply voltage from this instant appears across the load. Due to inductive load, the increase in current is gradual. Energy is stored in inductor during time $t_{01}$ to $t_{1} .$ At $t_{1},$ the supply voltage reverses, but the thyristor is kept conducting. This is due to the fact that current through the inductance cannot be reduced to zero.

During negative-voltage half-cycle, current continues to flow till the energy stored in the inductance is dissipated in the load-resistor and a part of the energy is fed-back to the source. Hence, due to energy stored in inductor, current , current continuous to flow upto instant $t_{11}$ at instant, $t_{11},$ the load-current is zero and due to negative supply voltage, thyristor turns-off.

At instant $t_{02},$ when again pulse is applied, the above cycle repeats. Hence the effect of the inductive load is increased in the conduction period of the SCR.

The half-wave circuit is not normally used since it produces a large output voltage ripple and is incapable of providing continuous load-current.

The average value of the load-voltage can be derived as:

Here, it has been assumed that in negative half-cycles, the SCR conducts for a period of $\alpha$

From the above equation, it is clear that the average load-voltage is reduced in case of inductive load. This is due to the conduction of SCR in negative cycle.