written 5.8 years ago by |
The circuit of the Cuk converter is shown in Fig.1.a. It consists of dc input voltage source VS, input inductor L1 , controllable switch S , energy transfer capacitor C1, diode D, filter inductor L2 , filter capacitor C, and load resistance R.
An important advantage of this topology is a continuous current at both the input and the output of the converter.
Disadvantages of the Cuk converter are a high number of reactive components and high current stresses on the switch, the diode, and the capacitor C1 .
The main waveforms in the converter are presented in Fig.1.b . When the switch is on, the diode is off and the capacitor C1 is discharged by the inductor L2 current. With the switch in the off state, the diode conducts currents of the inductors L1 and L2, whereas capacitor C1 is charged by the inductor L1 current.
To obtain the dc voltage transfer function of the converter, we shall use the principle that the average current through a capacitor is zero for steady-state operation. Let us assume that inductors L1 and L2 are large enough that their ripple current can be neglected. Capacitor C1 is in steady state if
IL2DT=IL1(1−D)T−−−−−(1)
For a lossless converter
PS=VSIL1=−VOIL2=PO−−−−−(2)
Combining these two equations, the dc voltage transfer function of the Cuk converter is,
MV≡VOVS=−D1−D−−−−−(3)
This voltage transfer function is the same as that for the buck- boost converter.
The boundaries between the CCM and DCM are determined by,
for L1
Lb1=(1−D)R2Df−−−−−(4)
and
for L2 , Lb2=(1−D)R2f−−−−−(5)
The output part of the Cuk converter is similar to that of the buck converter. Hence, the expression for the filter capacitor C is,
Cmin=(1−D)VO8VrL2f2−−−−−(6)
The peak-to-peak ripple voltage in the capacitor C1 can be estimated as
Vr1=DVOC1Rf−−−−−(7)
A transformer (isolated) version of the Cuk converter can be obtained by splitting capacitor C1 and inserting a high- frequency transformer between the split capacitors.