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Using Image Parameter method design a Low-pass composite filter with a cut-off frequency 2MHz and Impedance of 75$\Omega$. Place the Infinite attenuation pole at 2.05MHz

written 8.8 years ago by teamques10 ★ 69k

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rf modeling and antennas

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written 8.8 years ago by teamques10 ★ 69k

All of the component values can be found from table 8.2 for the constant K-section

$$L = \frac{2R_0}{w_c}= 11.94μH, C=\frac{2}{R_0w_c}=2.122nF$$

For the m-derived sharp-cutoff section

$$m=\sqrt{1}-(\frac{f_c}{f_∞})^2= 0.2195$$ $$\frac{mL}{2}= 1.310μH$$ $$mC= 465.8pF$$ $$\frac{1-m^2}{4m}L=12.94μH$$

For the m = 0.6 matching sections

$$\frac{mL}{2}=3.582μH$$ $$\frac{mC}{2} = 636.5pF$$ $$\frac{1-m^2}{2m}L=6.368μH$$

Final LPF Filter Representation:

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