0
7.4kviews
Using Image Parameter method design a Low-pass composite filter with a cut-off frequency 2MHz and Impedance of 75Ω. Place the Infinite attenuation pole at 2.05MHz
1 Answer
0
396views

All of the component values can be found from table 8.2 for the constant K-section

L=2R0wc=11.94μH,C=2R0wc=2.122nF

For the m-derived sharp-cutoff section

m=1(fcf)2=0.2195

mL2=1.310μH
mC=465.8pF
1m24mL=12.94μH

For the m = 0.6 matching sections

mL2=3.582μH

mC2=636.5pF
1m22mL=6.368μH

Final LPF Filter Representation:

enter image description here

Create a free account to keep reading this post.

and 5 others joined a min ago.

Please log in to add an answer.