written 8.4 years ago by
teamques10
★ 67k
|
All of the component values can be found from table 8.2 for the constant K-section
$$L = \frac{2R_0}{w_c}= 11.94μH, C=\frac{2}{R_0w_c}=2.122nF$$
For the m-derived sharp-cutoff section
$$m=\sqrt{1}-(\frac{f_c}{f_∞})^2= 0.2195$$ $$\frac{mL}{2}= 1.310μH$$ $$mC= 465.8pF$$ $$\frac{1-m^2}{4m}L=12.94μH$$
For the m = 0.6 matching sections
$$\frac{mL}{2}=3.582μH$$ $$\frac{mC}{2} = 636.5pF$$ $$\frac{1-m^2}{2m}L=6.368μH$$
Final LPF Filter Representation:
and 5 others joined a min ago.