In an AM receiver the loaded Q of an antenna circuit at the i/p to mixer is 100. calculate image frequnecy and its rejction at 1MHz.

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written 5.6 years ago by

teamques10 ★ 69k

modified 2.9 years ago by

pedsangini276 • 4.8k

Given:

Q = 100

Fs = 1MHz

Let IF = 455 Hz

$\therefore$ Image frequency fsi = fs + 2IF

$= [10^6 + 2 \times 455]$

= 910 MHz

Image frequency rejection ratio

$\alpha = \sqrt{1 + Q^2 P^2}$

$P = \frac{fsi}{fs} - \frac{fs}{fsi} = \frac{910}{81} - \frac{1}{910}$

= 909.99

$\therefore$ $\alpha = \sqrt{1 + (100)^2 \times (909.99)^2} = 82.82 $

electronic circuits and communication

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