written 8.8 years ago by | • modified 8.8 years ago |
π-model parameters
-
Mumbai University > EXTC > Sem 3 > Analog Electronics 1
Marks: 5 M
Year: Nov 2016
written 8.8 years ago by | • modified 8.8 years ago |
π-model parameters
-
Mumbai University > EXTC > Sem 3 > Analog Electronics 1
Marks: 5 M
Year: Nov 2016
written 8.8 years ago by | • modified 8.8 years ago |
Calculation for IB
Rth=R1||R2
Rth=100k||33k
R_{th}=24.8kΩ
E_{TH}=\frac{Vcc×R2}{R1+R2}
E_{TH}=4.46V
Fig1 Simplified circuit
Applying KVL to base emitter loop,
-E_{TH}-I_B R_{th} -V_{BE}-I_ER_E=0
Put I_E= (β+1)I_B
E_{TH}-I_B R_{th} -V_{BE}-(β+1)I_B R_E=0
I_B=\frac{E_{TH}-V_{BE}}{R_E (β+1)+R_{th}}
I_B=\frac{4.46-0.7}{1k(200+1)+24.8k}
I_B=16.65µA
Calculation for I_E and I_C
I_E=(β+1)I_B
I_E=201×16.65µA=3.346mA
I_C=βI_B=200×16.65µA=3.33mA
Calculation for …