Find the specific energy of flowing water through a rectangular channel of width 5m when the discharge is $10 m^3/s$ and depth of water is 3m

Given:

width of rectangular channel , h = 5m

discharge, q = $10 m^3/s$

depth of water , h = 3m

specific energy is given by equation (1)

$E = h + \frac{v^2}{2g}$

where, $v = \frac{q}{Area}$

$= \frac{10}{b \times h}$

$= \frac{10}{5 \times 3}$

$= \frac{2}{3}$

$\therefore$ $ E = 3 + \frac { (\frac{2}{3})^2} {2 \times 9.81}$

= 3 + 0.0226

= 3.0226 m