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Determine Euler cycle and path in graph shown below
1 Answer
written 2.8 years ago by |
Solution:
Let G be the given graph.
def(a) = 3
def(b) = 4
def(c) = 3
def(d) = 6
def(e) = 4
def(f) = 3
def(g) = 3
$\because$ The def of each vertex is not EVEN
$\therefore$ eulerian circuit is not present in Graph G
$\therefore$ Graph G is not eulerian graph.
$\therefore$ eulerian path is not present in G
$\therefore$ No eulerian path exist in G.