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Logically equivalent by developing a series of logical equivalence.
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written 3.0 years ago by | modified 2.5 years ago by |
Prove ∼ (PV( ∼ p^q)) and ∼ P ^ ∼q are logically equivalent by developing a series of logical equivalence.
solution :
Lets consider,
∼ (pv (∼ p ^ q))
= ∼ p ^ ∼ (\sim p ^ q) → Demorgan's Law
= ∼ p ^ p v ∼ …