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A pipe 0.6 m in diameter takes off water from reservoir 150 m high above the datum. The pipe is 5000 m long and is laid completely at datum level.

For the last 1200 m water is drawn by service pipe at uniform rate of 0.1m3/sec per 300 m. Find the head lost in the last 1200 m length of pipe. Take friction factor as 0.04 and velocity is zero at dead end.

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Data:-

D=0.6m,H=150m

L=5000m

Rate of water drawing=0.1m3s per 300 m

q=0.1300=3.33×104m3/sm

f=0.04,L0=1200m,vel. at dead end=0

To find:-

hf in last 1200 m of pipe=?

Solution:

enter image description here

Total distance Q0=1200300×0.1=0.4m3/sec

-As the water is drawn at uniform rate, therefore deriving expression for head loss for pipe having uniform water drawing rate.

-Consider a section at distance 'x' from the start of uniform withdrawal at q* per meter length

Discharge from x length

Qx=Q0(q.x)

in a small distance 'dx; head loss is dhf

dhf=f.dx.v2x2gD

but vx=QxA

vx=ΔQxπD2

v2x=[4(Q0q.x)πD2]2

dhf=f2gD×16(Q0qx)2π2D2.dx

dhf=8fπ2gD5×(Q0qx)2dx

Integrating

hf=L008fπ2gD5(Q0qx)2dx

=8fπ2.g.D5×13q[(Q0qL0)3Q30]

hf=8f3π2.g.D5×1q[(Q30(Q0qL0)3].........(1)

Equation (1) is expression for pipe in which water is drawn at uniform rate

Now, for last 1200 m, D=0.6m,q=3.33×104m3/sm,Q0=0.4m3/s,L0=1200m & f=0.04

equation (1) becomes

hf=8×0.043π2×9.81×0.65×13.33×104[0.43(3.33×104×1200)3]=2.7m

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