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Given the input parameters, simulation variable, output statistics for the queueing system.
written 5.6 years ago by gravatar for teamques10 teamques10 ★ 68k •   modified 4.6 years ago

Calculate the output statistics for the queueing system whose inter-arrival and service times for ten arrivals are given below:

Inter-arrival time - 8 6 1 8 3 8 7 2 3
Service time 4 1 4 3 2 4 5 4 5 3
computer simulation and modelling
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written 5.6 years ago by gravatar for teamques10 teamques10 ★ 68k •   modified 5.6 years ago

Solution:

Customer IAT AT ST Time
Service
Begin		 Time
Cust
waits
in queue		 Time
Service
ends		 Time
Cust
spends
in s/m		 Idle
time
server
1 - 0 4 0 0 4 4 0
2 8 8 1 8 0 9 1 4
3 6 14 4 14 0 18 4 5
4 1 15 3 18 3 21 6 0
5 8 23 2 23 0 25 2 2
6 3 26 4 26 0 30 4 1
7 8 34 5 34 0 39 5 4
8 7 41 4 41 0 45 4 2
9 2 43 5 45 2 50 7 0
10 3 46 3 50 4 53 7 0
- $\sum$ 46 - $\sum$ 35 - $\sum$ 9 - $\sum$ 44 $\sum$ 18

AT: Arrival time

IAT: Interarrival time

ST: Service Time

o/p statistics

  1. Avg waiting time for a customer = $\frac{9}{10} = 0.9$

  2. Probability of Idle server = $\frac{18}{53} = 0.34$

  3. Probability customer has to wait = $\frac{3}{10} = 0.3$

  4. Avg service time = $\frac{35}{10} = 3.5$

  5. Avg time between arrival = $\frac{46}{9} = 5.11$

  6. Avg waiting time for customer who waits = $\frac{9}{3} = 3$

  7. Avg time customer spent in the system = $\frac{44}{10} = 4.4$

  8. Max queue length = 1
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