An application has:

Given : 1000 heavy users at a peak of 2 IOPS

i.e. 1000 x 2 = 2000 IOPS and

2000 typical users at a pack of 1 IOPS

i.e. 2000 x 1 = 2000 IOPS

Solution : 80 total IOPS is 2000 + 2000 = 4000 IOPS

• Also it is given that Application experiences an overhead of 20% for other workloads.

i.e. $4000 \times \frac{20}{100} = 800$ IOPS

Therefore, total IOPS required by application is = 4000 + 800 (overheat)

Now, to calculate IOPS required by Raid 1, Raid 3, Raid 5, and Raid 6.

Read/write Ratio i.e. Read = 0.66 and write = 0.33