Find Cosine Distance between the d1 and d2 vectors:

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written 5.6 years ago by

swatisharma • 1.3k

modified 4.6 years ago by

prashantsaini • 0

Index	1	2	3	4	5	6	7	8	9	10
d1	5	2	1	0	0	0	0	1	3	7
d2	5	2	1	0	0	1	2	2	0	2

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1 Answer

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written 5.6 years ago by

teamques10 ★ 68k

Cosine distance $(d_1, d_2) = \frac{d1.d2}{||d1||.||d2||}$

d1.d2 = 5 x 5 + 2 x 2 + 1 x 1 + 0 + 0 + 0 + 0 + 1 x 2 + 0 + 7 x 2 = 25 + 4 + 1 + 2 + 14 = 46

|| d1 || = $\sqrt{25+4+1+1+9+49} = \sqrt{89}$

|| d2 || = $\sqrt{25 + 4 + 1 + 1 + 4 + 4 + 4} = \sqrt{43}$

Cosine distance (d1, d2) = $\frac{46}{ \sqrt{89}. \sqrt{43}} = \frac{46}{ \sqrt{3827}}$

= $\frac{46}{61.86}$ = 0.74

$\theta$ = cos + (0.74)

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