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MODULE 04 - Q.4

written 6.0 years ago by teamques10 ★ 69k

modified 3.0 years ago by pedsangini276 • 4.8k

Draw AFD,SFD & BMD for frame

structural analysis

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1 Answer

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written 6.0 years ago by teamques10 ★ 69k

•   modified 6.0 years ago

Solution:

$\sum M_A=0$

$M_A=12\times 5+ 10\times 3 \times \frac{3}{2}=0$

$M_A=15kN.m$

$\sum F_y=0(\uparrow +ve)$

$V_A-10\\times 3=0$

$V_A=30kN$

$\sum F_x=0(\rightarrow +ve)$

$H_A-12=0$

$H_A=12kN$

$BM_B=15-12\times 5=-45kN.m$

(1)Consider part AB:

(2)Consider part BC:

(3)Consider part CD:

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