One input to AM modulation is 800 KHz carrier with an amplitude of 10 vp. The second input is 10 KHZ modulating signal that is sufficient to cause a change in the o/p wave of

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written 6.0 years ago by

teamques10 ★ 69k

modified 6.0 years ago by

ankitpandey • 100

$\pm5.5 vp$ .

Determine

(i) upper and lower side frequency

(ii) modulation coefficient and percent modulation

(iii) Draw output frequency spectrum

(iv) draw modulated wave showing maxima and minima of wave forms

Subject: Priniciples of Communication Engineering

Difficulty : Medium

Marks : 10

principles of communication network

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1 Answer

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written 6.0 years ago by

yashbeer ★ 11k

• modified 6.0 years ago

Solution:

Given: $f_c$ = 800 KHz

$f_m$ = 10 KHz

$V_c$ = 10 v

$V_m$ = 5.5 v

$\therefore V_m = 5.5 v$

(i) Upper and lower side band frequency

Upper side band frequency

$f_{usb}$ = $f_c$ + $f_m$

= 800 + 10

= 810 KHz

Lower side band frequency …

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