written 2.6 years ago by |
Diagram of broach :
Let,
n = Total number of teeth in the broach
L = Effective length of a broach in mm
P - Tool pitch in mm
L = Length to be broached in mm
t - Rise per tooth in mm
$n_s$ = Number of safety teeth
$n_f$ Number of finishing teeth ( Range, 3 to 6 )
1) Tool pitch (p) : p = 1.75 $\sqrt{l}$
2) Rise per tooth (t) :
Total rise = No. of teeth in broach x rise per tooth
= n x t
3) Total number of teeth in the broach (n)
n = (Roughing teeth) + (finishing teeth)
n = ( $\frac{depth \ of \ cut}{cut \ per \ tooth}$ ) + ( $n_s$ + $n_f$)
n = ( $\frac{total \ rise}{rise \ per \ tooth}$ ) + ( $n_s$ + $n_f$)
4) Effective length (L)
L = No. of teeth in broach x pitch
= n x p
5) Total load on a broach (F)
a) for round holes
f = Hole circumference x N X t x K
= $\pi$ d x N X t x K
b) For square holes
f = Hole perimeter x N X t x K
= 4 H x N x t x K
Where,
d = finished hole dia in mm
N = Maximum no. of teeth cutting at a time
t = Rise per tooth in mm
K = Force required to cut 1 mm and 2 mm of metal at a given rise per tooth
H = Finished length of one side of square hole in mm
6) Total effective length ( $L_T$ )
$L_T$ = Length of roughing teeth + Length of finishing teeth = No. of roughing teeth x pitch + No. of finishing teeth x $\frac{pitch}{2}$
$L_T$ = $n_r$ x p + $n_f$ x $\frac{p}{2}$