0
566views
Module 6 : Unit 2
1 Answer
0
2views

2. Low power design consideration

Static

$P_{ds}=V_{DD}.I_D$

dynamic

$Q=C_oV_{DD}$

$= V_{DD}.Q/t$

$=V_{DD}^2 . C_o.f$

Total average $P= V_{DD}.I_D+ V_{DD}^2.C_o.f$

3. Interconnect scaling

W , t, td = three interconnect parameter

Resistance:

W’=w/s

R=Rs(L/w)

R’=R=Rs=sRs=sr

R’(line)=sr(line)

But l’=l/s

R’(line)= r(line)

Cap:

$c^{'} = E_o [1.15(w^{'}/t_d) + 2.8(t/t_d)^{0.222}]$

C’=C/s

$C’_{line}= C_{line}/S^2$

4. Input and output protection circuit

  • CM OS chips must be electrostatic discharge protection circuit at its input

  • ESD event is the transfer of charge between two bodies at different potential

  • ESD generates High Voltage or high peak current that may damage IC

  • $E_{ox} = \frac{V_G}{t_{ox}}$

Oxide thickness in everything electric field are quite large

  • A Tox in decreasesEox increase also Vgt increases Eox increases beyond maximum electric field and destroy it completly

enter image description here

  • During PSD Hai positive voltage is applied at iPad the D1 and D2 under breakdown and thus prevents resistance drop the voltage level along IP line

enter image description here

Normal ops -D1 and D2 = RB

If i/p voltage increases above Vdd D1 conducts which D2 conducts with Vin decreases ground

enter image description here

5. Cross talks

  • Unwanted transfer of signal from 1 place to another through coupling cap is crosstalk

  • Consider 2 wires running in parallel

Wire 1 = C1 and V1 and wire 2= C2 and V1

  • If isolated Q1=C1V1 and Q2=C2V2

  • Since coupled coupling cap must be introduced,

    Q1=C1V1 +CcoupV2

Q2=CcoupV1+CCcoup

Diff

$i_1=dQ_1/dt=C_1dV_1/t+C_{coup} dV_2/dt$

$i_2=dQ_2/dt =C_{coup} dV_1/dt +C_2dV_2/dt$

  • When voltage of one line changes i1 and I2 also changes lead to decoration speed health causes crosstalk

  • To avoid

  • i) To crosstalk increase spacing between wire which decrease Ccoup

  • ii) Place ground lines on vdd between signal lines

Please log in to add an answer.