written 5.7 years ago by |
It memory cell (DRAM)
- Write
-1. Drive bit line
-2. Select Rou
- Read
precharge bit line to $V_{dd}/2$.
Select row
Cell and bit line share charges - Minute voltage change on BL
Sense (fancy sense amp.).Can detect changes of 1 million eelectrons
Write: restore the valve
Refresh
- Just to do dummy read to every ccel
3 - T DRAM cell with the pull-up and read/unite circuity
RD/WR Access
DRAM operation mode
Async mode – uses RAS and CAS
sync mode
leakage current
$I_{sub}$ – through cell access transfer
$I_j$—junctionleakage current at storage
$I_{cell}$ to cell tunneling I three thin dieletric $T_{OX}$
$I_{tunnelling}$ $I_{leakage}$ accross the field oxide
6T SRAM
Read operation.
1.Assume logic“0” started at the left side and logic “1” at the right.
2.M2 -M5 =OFF and M1 M6 =On (linear)
3.V1=0 v and V2= Vod before M3&M4 are ON
DL—Precharged to Vdd
row selection line = low in stand by raised to Vo
M3- M4= on mem cell connected to dL
M4—D & S (same potential) no current voltage is maintained.
M3- M1 conducts current flow M3—M1—G cap discharges slowly voltage lecel of col C drops slightly.
Voltage diff is developed at 0 l sense amplifier is ON diff in C and C is fed to sense ap to generate a valid low 0/10 – stored in data buffer
upon completion – WL = 0
WRITE OPERATION
Assume logic “1” is started
M1-M6 = off and M5- M2 = on (linear)
V1= Vdd and V2 = ov before M3 M4 are ON
Row sdetion line–low in stand by – raised to VDd
M3- M4 = on Mem cell are connected to dataliareTo change stored info that is to forveV1 =0V and V2=VDd , the V1 node voltage must be reduced below VTh of M2 so that M2 turn off firs
The M2 – forced in cutoff mode during write “0” operation. Subsequently M1 turn on changing the stored info